How to remove the first occurrence of an item in a list in Python
:
This post will show you how to remove the first occurrence of an item from a list in Python
. The program will use one predefined list and one number to remove from the list. There are different ways to solve this problem in Python
. I will show you four different ways.
Method 1: By using the remove()
method:
The remove()
method of Python
list removes the first occurrence of an element from a list. This method takes the element as its parameter and removes its first instance. The syntax of the remove()
method is:
list.remove(e)
e
is the element to remove. If the element doesn’t exists in the list, it throws aValueError
.- The return value of this method is
None
or it returns nothing.
Let’s take a look at the following example:
days = ['sun', 'mon', 'tues', 'thurs', 'fri', 'sat']
print(f'Given list: {days}')
days.remove('tues')
print(f'Final list: {days}')
- It has a predefined list of strings
days
. - It uses the
remove()
method to remove the string from the list. - It prints the content of the list before and after the string is removed.
If you run this program, it will print:
Given list: ['sun', 'mon', 'tues', 'thurs', 'fri', 'sat']
Final list: ['sun', 'mon', 'thurs', 'fri', 'sat']
The string 'tues'
is removed from the list.
If the list has multiple instances of the element we are trying to remove, it will remove the first occurrence of the element. Let’s consider the following example:
days = ['sun', 'mon', 'tues', 'thurs', 'fri', 'tues', 'sat']
print(f'Given list: {days}')
days.remove('tues')
print(f'Final list: {days}')
- Download it on GitHub
The list days
includes two instances of the string 'tues'
. The remove()
method will remove the first one from the list. If you run this program, it will print:
Given list: ['sun', 'mon', 'tues', 'thurs', 'fri', 'tues', 'sat']
Final list: ['sun', 'mon', 'thurs', 'fri', 'tues', 'sat']
Method 2: By using the pop()
method:
The pop
method is another method to remove Python
list elements. This method takes the index of the element to remove as its parameter. The syntax of the pop
method is:
list.pop(i)
- The
i
is the only parameter requires. It is the index of the element to remove from the list. - The parameter
i
is optional. If we don’t provide its value, it will remove the last element of the list, i.e.-1
is passed as the parameter. - The
pop
method supports negative indexing. e.g. if we pass -1, it will remove the last element, -2 will remove the second last element etc. - The
pop
method returns the deleted item. - For invalid index value, it throws
IndexError: pop index out of range
exception.
We can use the index()
method to get the index of the first occurrence of an element. Note that this method throws ValueError
if the element is not found in the list.
days = ['sun', 'mon', 'tues', 'thurs', 'fri', 'tues', 'sat']
print(f'Given list: {days}')
days.pop(days.index('tues'))
print(f'Final list: {days}')
- Download it on GitHub
It will print:
Given list: ['sun', 'mon', 'tues', 'thurs', 'fri', 'tues', 'sat']
Final list: ['sun', 'mon', 'thurs', 'fri', 'tues', 'sat']
Method 3: By using the del
operator:
The del
operator is similar to the pop()
method. The only difference is that it doesn’t return the deleted item. The following program shows how we can use the del
operator to remove an item from a list:
days = ['sun', 'mon', 'tues', 'thurs', 'fri', 'tues', 'sat']
print(f'Given list: {days}')
del days[days.index('tues')]
print(f'Final list: {days}')
It will print the same output.
- Download it on GitHub
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