Introduction :
This program will show you how to get the cube sum of first n natural numbers in python. The program will take the value of n as an input from the user, calculate the sum of cube and print it out.
We will solve this problem by using one loop and recursively.
Method 1: Using a loop :
Get the value of n, call one method to find the total cube sum and use one loop to find that out :
def findCubeSum(n):
sum = 0
for value in range(1, n+1):
sum += value**3
return sum
n = int(input("Enter the value of n : "))
print("Cube sum : ", findCubeSum(n))
Sample Output :
Enter the value of n : 5
Cube sum : 225
Enter the value of n : 10
Cube sum : 3025
Enter the value of n : 4
Cube sum : 100
Method 2: Recursive approach :
We can also call the same method recursively to find out the cube sum :
def findCubeSum(n):
if(n<=1):
return 1;
return n**3 + findCubeSum(n-1)
n = int(input("Enter the value of n : "))
print("Cube sum : ", findCubeSum(n))
Here, findCubeSum method is called recursively. It will print the same output as the above example.
